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A skydiver jumps out of a helicopter and falls freely for 14.4 s before opening the parachute. What is the skydivers speed (in m/s) when the parachute opens?

Answer :

MathPhys

Answer:

141 m/s

Explanation:

Given:

v₀ = 0 m/s

a = 9.8 m/s²

t = 14.4 s

Find: v

v = at + v₀

v = (9.8 m/s²) (14.4 s) + 0 m/s

v = 141 m/s

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