Answer :
Answer:
a) p =100
b) [tex] D = (-\infty, 100) \cup (100, \infty)[/tex]
c) But the real practical domain would be:
[tex] D= [0,100)[/tex]
Since the percent of particulate pollution removed from an industrial plant can't be negative or higher or equal than 100
Step-by-step explanation:
For this case we have the following function:
[tex] C(p) = \frac{6800p}{100-p}[/tex]
Part a
For this case the function is not defined at p =100 since:
[tex] C(100) = \frac{6800*100}{100-100} =DNE[/tex]
Is not defined since we can't divide by 0.
So then the answer would be p =100
Part b
For this case since the function is not defined at p =100 the domain would be given by:
[tex] D = (-\infty, 100) \cup (100, \infty)[/tex]
Part c
But the real practical domain would be:
[tex] D= [0,100)[/tex]
Since the percent of particulate pollution removed from an industrial plant can't be negative or higher or equal than 100