Answer :
Answer:
Electroosmotic velocity will be equal to [tex]1.6\times 10^{-4}m/sec[/tex]
Explanation:
We have given applied voltage v = 100 volt
Length of capillary L = 5 mm = 0.005 m
Zeta potential of the capillary surface [tex]\xi =80mV=0.08volt[/tex]
Dielectric constant of glass is between 5 to 10 here we are taking dielectric constant as [tex]\epsilon =10[/tex]
Viscosity of glass is [tex]\eta =10^8[/tex]
Electroosmotic velocity is given as [tex]v_{eo}=\frac{\epsilon \xi }{\eta }\times \frac{v}{L}[/tex]
[tex]v_{eo}=\frac{10\times 0.08 }{10^8 }\times \frac{100}{0.005}=1.6\times 10^{-4}m/sec[/tex]
So Electroosmotic velocity will be equal to [tex]1.6\times 10^{-4}m/sec[/tex]